What will be the output of the program?

#include<stdio.h>
int main()
{
    char ch;
    ch = 'A';
    printf("The letter is");
    printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch);
    printf("Now the letter is");
    printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A');
    return 0;
}

What will be the output of the program?

#include<stdio.h>
int main()
{
    int i=2;
    int j = i + (1, 2, 3, 4, 5);
    printf("%d\n", j);
    return 0;
}

Associativity has no role to play unless the precedence of operator is same.

The expression of the right hand side of || operators doesn't get evaluated if the left hand side determines the outcome.

In the expression a=b=5 the order of Assignment is NOT decided by Associativity of operators

Associativity of an operator is either Left to Right or Right to Left.

Are the following two statement same?
1. a <= 20 ? (b = 30): (c = 30);
2. (a <=20) ? b : (c = 30);

Two different operators would always have different Associativity.

Will the expression *p = p be disallowed by the compiler?

Every operator has an Associativity