Assume integer is 2 bytes wide. How many bytes will be allocated for the following code?

#include<stdio.h>
#include<stdlib.h>
#define MAXROW 3
#define MAXCOL 4

int main()
{
    int (*p)[MAXCOL];
    p = (int (*) [MAXCOL])malloc(MAXROW *sizeof(*p));
    return 0;
}

Assume integer is 2 bytes wide. What will be the output of the following code?

#include<stdio.h>
#include<stdlib.h>
#define MAXROW 3
#define MAXCOL 4

int main()
{
    int (*p)[MAXCOL];
    p = (int (*) [MAXCOL])malloc(MAXROW *sizeof(*p));
    printf("%d, %d\n", sizeof(p), sizeof(*p));
    return 0;
}

How many bytes of memory will the following code reserve?

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int *p;
    p = (int *)malloc(256 * 256);
    if(p == NULL)
        printf("Allocation failed");
    return 0;
}

Point out the error in the following program.

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int *a[3];
    a = (int*) malloc(sizeof(int)*3);
    free(a);
    return 0;
}

Point out the error in the following program.

#include<stdio.h>
#include<stdlib.h>

int main()
{
    char *ptr;
    *ptr = (char)malloc(30);
    strcpy(ptr, "RAM");
    printf("%s", ptr);
    free(ptr);
    return 0;
}

Point out the correct statement will let you access the elements of the array using 'p' in the following program?

#include
#include

int main()
{
    int i, j;
    int(*p)[3];
    p = (int(*)[3])malloc(3*sizeof(*p));
    return 0;
}

Which of the following statement is correct prototype of the malloc() function in c ?

Point out the correct statement which correctly free the memory pointed to by 's' and 'p' in the following program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
    struct ex
    {
        int i;
        float j;
        char *s
    };
    struct ex *p;
    p = (struct ex *)malloc(sizeof(struct ex));
    p->s = (char*)malloc(20);
    return 0;
}

Point out the correct statement which correctly allocates memory dynamically for 2D array following program?

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int *p, i, j;
    /* Add statement here */
    for(i=0; i<3; i++)
    {
        for(j=0; j<4; j++)
        {
            p[i*4+j] = i;
            printf("%d", p[i*4+j]);
        }
    }
    return 0;
}

malloc() returns a float pointer if memory is allocated for storing float's and a double pointer if memory is allocated for storing double's.