A short integer is at least 16 bits wide and a long integer is at least 32 bits wide.

Which of the following correctly shows the hierarchy of arithmetic operations in C?

In which order do the following gets evaluated
1. Relational
2. Arithmetic
3. Logical
4. Assignment

Associativity has no role to play unless the precedence of operator is same.

If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)?

#include<stdio.h>
#include<math.h>
int main()
{
    float a=5.375;
    char *p;
    int i;
    p = (char*)&a;
    for(i=0; i<=3; i++)
        printf("%02x\n", (unsigned char)p[i]);
    return 0;
}

A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?

What will be the output of the program?

#include<stdio.h>
int sumdig(int);
int main()
{
    int a, b;
    a = sumdig(123);
    b = sumdig(123);
    printf("%d, %d\n", a, b);
    return 0;
}
int sumdig(int n)
{
    int s, d;
    if(n!=0)
    {
        d = n%10;
        n = n/10;
        s = d+sumdig(n);
    }
    else
        return 0;
    return s;
}

Point out the error in the program

f(int a, int b)
{
    int a;
    a = 20;
    return a;
}

What will be the output of the program?

#include<stdio.h>
#define SQUARE(x) x*x

int main()
{
    float s=10, u=30, t=2, a;
    a = 2*(s-u*t)/SQUARE(t);
    printf("Result = %f", a);
    return 0;
}

Preprocessor directive #undef can be used only on a macro that has been #define earlier